Display true if the given string contains a "bob" string, but where the middle 'o' char can be any char.
Test Case |
Input | Program Output |
---|---|---|
1 | abcbob | true |
2 | b9b | true |
3 | bac | false |
Solutions: | python | raptor |
We'll say that a String is xy-balanced if for all the 'x' chars in the string, there is a 'y' char somewhere later in the string. So "xxy" is balanced, but "xyx" is not. Return true if the given string is xy-balanced.
Test Case |
Input | Program Output |
---|---|---|
1 | aaxbby | true |
2 | aaxbb | false |
3 | yaaxbb | false |
Solutions: | python | raptor |
Given two strings, A and B, create a bigger string made of the first char of A, the first char of B, the second char of A, the second char of B, and so on. Any leftover chars go at the end of the result.
Test Case |
Input |
Input | Program Output |
---|---|---|---|
1 | abc | xyz | true |
2 | Hi | There | false |
3 | xxxx | There | true |
Solutions: | python | raptor |